-[9z-(20z+3)]=3+(10z+1)

Solution for -[9z-(20z+3)]=3+(10z+1) equation:

Simplifying
-1[9z + -1(20z + 3)] = 3 + (10z + 1)

Reorder the terms:
-1[9z + -1(3 + 20z)] = 3 + (10z + 1)
-1[9z + (3 * -1 + 20z * -1)] = 3 + (10z + 1)
-1[9z + (-3 + -20z)] = 3 + (10z + 1)

Reorder the terms:
-1[-3 + 9z + -20z] = 3 + (10z + 1)

Combine like terms: 9z + -20z = -11z
-1[-3 + -11z] = 3 + (10z + 1)
[-3 * -1 + -11z * -1] = 3 + (10z + 1)
[3 + 11z] = 3 + (10z + 1)

Reorder the terms:
3 + 11z = 3 + (1 + 10z)

Remove parenthesis around (1 + 10z)
3 + 11z = 3 + 1 + 10z

Combine like terms: 3 + 1 = 4
3 + 11z = 4 + 10z

Solving
3 + 11z = 4 + 10z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-10z' to each side of the equation.
3 + 11z + -10z = 4 + 10z + -10z

Combine like terms: 11z + -10z = 1z
3 + 1z = 4 + 10z + -10z

Combine like terms: 10z + -10z = 0
3 + 1z = 4 + 0
3 + 1z = 4

Add '-3' to each side of the equation.
3 + -3 + 1z = 4 + -3

Combine like terms: 3 + -3 = 0
0 + 1z = 4 + -3
1z = 4 + -3

Combine like terms: 4 + -3 = 1
1z = 1

Divide each side by '1'.
z = 1

Simplifying
z = 1